If $a, b,$ and $c$ are the roots of $x^3+4x+1=0$,then $\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}=$

  • A
    $2$
  • B
    $3$
  • C
    $4$
  • D
    $-4$

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