If $\tan \beta = \frac{\tan \alpha + \tan \gamma}{1 + \tan \alpha \tan \gamma}$,then $\frac{\sin 2 \alpha + \sin 2 \gamma}{1 + \sin 2 \alpha \sin 2 \gamma} = $

  • A
    $\sin 2 \beta$
  • B
    $\cos 2 \beta$
  • C
    $\tan 2 \beta$
  • D
    $\sec 2 \beta$

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