If A is a matrix of order 3 whose determinant | vedclass

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(B) We know that for a square matrix $A$ of order $n$,the determinant of its adjoint matrix is given by the formula: $\operatorname{det}(\operatorname

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$36$

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(B) We know that for a square matrix $A$ of order $n$,the determinant of its adjoint matrix is given by the formula: $\operatorname{det}(\operatorname{adj} A) = (\operatorname{det} A)^{n-1}$.Given that $A$ is a matrix of order $n = 3$ and its determinant $\operatorname{det} A = 6$.Substituting these values into the formula,we get:$\operatorname{det}(\operatorname{adj} A) = (6)^{3-1}$$\operatorname{det}(\operatorname{adj} A) = (6)^2$$\operatorname{det}(\operatorname{adj} A) = 36$.Therefore,the correct option is $B$.

If $A$ is a matrix of order $3$ whose determinant is equal to $6$,then $\operatorname{det}(\operatorname{adj} A) = $

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