If $\tanh ^{-1} x = a \log \left(\frac{1+x}{1-x}\right)$,$|x| < 1$,then $a$ is equal to

  • A
    $1$
  • B
    $2$
  • C
    $\frac{1}{2}$
  • D
    $\frac{1}{4}$

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