If $\operatorname{sech}^{-1} x = \log 2$ and $\operatorname{cosech}^{-1} y = -\log 3$, then $(x + y) = $

  • A
    $\frac{1}{6}$
  • B
    $\frac{1}{20}$
  • C
    $6$
  • D
    $\frac{5}{6}$

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