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(D) Given $f(x) = [\frac{x}{5}]$. We need to find the range of $f(x)$ for $|x| < 71$. This is equivalent to $-71 < x < 71$. Dividing by $5$,we get $-\

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$\{-15, -14, \ldots, 0, \ldots, 13, 14\}$

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(D) Given $f(x) = [\frac{x}{5}]$. We need to find the range of $f(x)$ for $|x| This is equivalent to $-71 Dividing by $5$,we get $-\frac{71}{5} This simplifies to $-14.2 Since $f(x) = [\frac{x}{5}]$,the possible integer values for $f(x)$ are the integers in the interval $(-14.2, 14.2)$. The smallest integer greater than $-14.2$ is $-14$,and the largest integer less than $14.2$ is $14$. Wait,let us re-evaluate the bounds: If $x$ is slightly greater than $-71$,say $x = -70.9$,then $f(x) = [\frac{-70.9}{5}] = [-14.18] = -15$. If $x$ is slightly less than $71$,say $x = 70.9$,then $f(x) = [\frac{70.9}{5}] = [14.18] = 14$. Thus,the set of values is $\{-15, -14, \ldots, 0, \ldots, 13, 14\}$.

If $f: R \rightarrow R$ is defined by $f(x) = [\frac{x}{5}]$ for $x \in R$,where $[y]$ denotes the greatest integer not exceeding $y$,then $\{f(x) : |x| < 71\}$ is equal to

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