If $f:[-6,6] \rightarrow R$ is defined by $f(x)=x^2-3$ for $x \in R$,then $(f \circ f \circ f)(-1)+(f \circ f \circ f)(0)+(f \circ f \circ f)(1)$ is equal to

  • A
    $f(4 \sqrt{2})$
  • B
    $f(3 \sqrt{2})$
  • C
    $f(2 \sqrt{2})$
  • D
    $f(\sqrt{2})$

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