If $y=\tan ^{-1}\left(\frac{\sqrt{1+a^2 x^2}-1}{a x}\right)$,then $\left(1+a^2 x^2\right) y^{\prime \prime}+2 a^2 x y^{\prime}$ is equal to

  • A
    $-2 a^2$
  • B
    $a^2$
  • C
    $2 a^2$
  • D
    $0$

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