If $\cos ^{-1}\left(\frac{y}{b}\right)=2 \log \left(\frac{x}{2}\right)$,where $x>0$,then $x^2 \frac{d^2 y}{d x^2}+x \frac{d y}{d x}$ is equal to

  • A
    $4 y$
  • B
    $-4 y$
  • C
    $0$
  • D
    $-8 y$

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