If $\frac{2 x^2+5 x+6}{(x+2)^3}=\frac{a}{x+2}+\frac{b}{(x+2)^2}+\frac{c}{(x+2)^3}$ then $a \cdot b+b \cdot c+c \cdot a=$

  • A
    $28$
  • B
    $14$
  • C
    -$10$
  • D
    -$8$

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