If 1 L of an ideal gas at a pressure of 20 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an isothermal reversible expansion of an ideal gas,the heat absorbed $(q_{rev})$ is equal to the work done by the system $(-w_{rev})$.$q_{rev}

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) For an isothermal reversible expansion of an ideal gas,the heat absorbed $(q_{rev})$ is equal to the work done by the system $(-w_{rev})$.$q_{rev} = -w_{rev} = 2.303 P_1 V_1 \log \frac{V_2}{V_1}$Given $P_1 = 20 \ atm$,$V_1 = 1 \ L$,and $q_{rev} = 92.12 \ L \ atm$.$92.12 = 2.303 	imes 20 	imes 1 	imes \log \frac{V_2}{1}$$92.12 = 46.06 \log V_2$$\log V_2 = \frac{92.12}{46.06} = 2$$V_2 = 10^2 = 100 \ L$Thus,$X = 100$.

If $1 \ L$ of an ideal gas at a pressure of $20 \ atm$ expands isothermally and reversibly to a final volume of '$X$' $L$ by absorbing $92.12 \ L \ atm$ heat,'$X$' (in $L$) is

Similar Questions

During the free expansion of an ideal gas in an isolated chamber,

The temperature of the system decreases in an

For the exothermic reaction of $1 \ mol$ of $Zn$ dust with $1 \ mol$ of $H_2SO_4$ in a bomb calorimeter,the relationship between $\Delta U$ and $w$ is .....

When a gas undergoes adiabatic expansion,it gets cooled due to

Calculate the change in internal energy $(\Delta U)$ if $\Delta H = -92.2\, kJ$,$P = 40\, atm$,and $\Delta V = -1\, L$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module