If $\alpha, \beta, \gamma$ are the roots of the equation $x^3+a x^2-b x+c=0$,then $\sum \beta^2(\gamma+\alpha) = $

  • A
    $\frac{a^2+b-c}{3 a b}$
  • B
    $a c+b^3$
  • C
    $\frac{b c+a^2}{3 a b}$
  • D
    $a b+3 c$

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