If m_1, m_2, m_3 and m_4 respectively denote | vedclass

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(C) Let $z_1 = 1+4i, z_2 = 3+i, z_3 = 1-i$ and $z_4 = 2-3i$.The modulus of a complex number $z = a+bi$ is given by $|z| = \sqrt{a^2+b^2}$.Calculating

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$m_3 < m_2 < m_4 < m_1$

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(C) Let $z_1 = 1+4i, z_2 = 3+i, z_3 = 1-i$ and $z_4 = 2-3i$.The modulus of a complex number $z = a+bi$ is given by $|z| = \sqrt{a^2+b^2}$.Calculating the moduli:$m_1 = |1+4i| = \sqrt{1^2+4^2} = \sqrt{1+16} = \sqrt{17}$$m_2 = |3+i| = \sqrt{3^2+1^2} = \sqrt{9+1} = \sqrt{10}$$m_3 = |1-i| = \sqrt{1^2+(-1)^2} = \sqrt{1+1} = \sqrt{2}$$m_4 = |2-3i| = \sqrt{2^2+(-3)^2} = \sqrt{4+9} = \sqrt{13}$Comparing the values: $\sqrt{2} < \sqrt{10} < \sqrt{13} < \sqrt{17}$,which implies $m_3 < m_2 < m_4 < m_1$.

If $m_1, m_2, m_3$ and $m_4$ respectively denote the moduli of the complex numbers $1+4 i, 3+i, 1-i$ and $2-3 i$,then the correct one,among the following is

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