If $\sum_{r=0}^{20} {}^{20+r}C_r = \frac{p}{q} {}^{40}C_{20}$ and $GCD(p, q) = 1$,then $p^2 - q^2 =$

  • A
    $1302$
  • B
    $1220$
  • C
    $1240$
  • D
    $1364$

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