If $0 < A < B < \frac{\pi}{4}$,$\cos (A+B) = \frac{11}{61}$ and $\sin (A-B) = \frac{24}{25}$,then $\sin 2A + \sin 2B = $

  • A
    $\frac{684}{1525}$
  • B
    $\frac{156}{1525}$
  • C
    $\frac{168}{305}$
  • D
    $\frac{137}{305}$

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