Class 11MathematicsTrigonometric FunctionsTrigonometrical ratios of sum and difference of two and three angles
Difficultयदि $0 < A < B < \frac{\pi}{4}$,$\cos (A+B) = \frac{11}{61}$ और $\sin (A-B) = \frac{24}{25}$ है,तो $\sin 2A + \sin 2B = $
- A$\frac{684}{1525}$
- B$\frac{156}{1525}$
- C$\frac{168}{305}$
- D$\frac{137}{305}$
Explore More
Similar Questions
यदि $\cos (\alpha+\beta)=\frac{4}{5}$,$\sin (\alpha-\beta)=\frac{5}{13}$ और $\alpha, \beta$ का मान $0$ और $\frac{\pi}{4}$ के बीच है,तो $\tan 2 \alpha$ का मान ज्ञात कीजिए।
DifficultAP EAMCET 2002
View Solutionयदि $\cos (A-B)=3/5$ और $\tan A \tan B=2$ है,तो निम्नलिखित में से कौन सा सत्य है?
DifficultTS EAMCET 2007
View Solution$\cos \alpha \sin (\beta - \gamma ) + \cos \beta \sin (\gamma - \alpha ) + \cos \gamma \sin (\alpha - \beta ) = $
Easy
View Solution$\cos ^4 \frac{\pi}{24} - \sin ^4 \frac{\pi}{24} = $
मान लीजिए $\tan \alpha = \frac{a}{a+1}$ और $\tan \beta = \frac{1}{2a+1}$, तो $\alpha + \beta$ का मान क्या है?
MediumWBJEE 2011
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo