If $0 < \theta < \frac{\pi}{2}$,then the solution of the equation $\sin \theta - 3 \sin 2 \theta + \sin 3 \theta = \cos \theta - 3 \cos 2 \theta + \cos 3 \theta$ is

  • A
    $\frac{\pi}{16}$
  • B
    $\frac{\pi}{12}$
  • C
    $\frac{\pi}{8}$
  • D
    $\frac{\pi}{6}$

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