If y=mx+4 (n0 is a typo,likely m0 or irrele | vedclass

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(B) The equation of the tangent to the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$ is $y = mx \pm \sqrt{a^2m^2 - b^2}$.Given the tangent $y = mx

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$\left(\frac{25}{4}, \frac{9}{4}\right)$

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(B) The equation of the tangent to the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$ is $y = mx \pm \sqrt{a^2m^2 - b^2}$.Given the tangent $y = mx + 4$,we have $c = 4$.Comparing $c^2 = a^2m^2 - b^2$,we get $16 = 25m^2 - 9$.$25m^2 = 25 \Rightarrow m^2 = 1$. Since $m$ is usually positive for such forms,$m = 1$.The point of contact for a tangent $y = mx + c$ to the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$ is given by $\left(\frac{a^2m}{c}, \frac{b^2}{c}ight)$.Substituting $a^2 = 25, b^2 = 9, m = 1, c = 4$:Point of contact = $\left(\frac{25 	imes 1}{4}, \frac{9}{4}ight) = \left(\frac{25}{4}, \frac{9}{4}ight)$.

If $y=mx+4$ ($n>0$ is a typo,likely $m>0$ or irrelevant) is a tangent to the hyperbola $\frac{x^2}{25}-\frac{y^2}{9}=1$,then the point of contact of this tangent is

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