If $f: [-2, 2] \rightarrow R$ is defined by $f(x) = \begin{cases} \frac{\sqrt{1 + cx} - \sqrt{1 - cx}}{x}, & -2 \leq x < 0 \\ \frac{x + 3}{x + 1}, & 0 \leq x \leq 2 \end{cases}$ is continuous on $[-2, 2]$,then $c$ is equal to

  • A
    $\frac{2}{\sqrt{3}}$
  • B
    $3$
  • C
    $\frac{3}{2}$
  • D
    $\frac{3}{\sqrt{2}}$

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Let $f: R \rightarrow R$ be defined as:
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