If $\frac{3x+2}{(x+1)(2x^2+3)} = \frac{A}{x+1} + \frac{Bx+C}{2x^2+3}$, then $A+C-B$ is equal to :

  • A
    $0$
  • B
    $2$
  • C
    $3$
  • D
    $5$

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