If $y = \frac{\tan x \cos^{-1} x}{\sqrt{1-x^2}}$, then the value of $\frac{dy}{dx}$ when $x = 0$ is:

  • A
    $0$
  • B
    $\frac{\pi}{2}$
  • C
    $1$
  • D
    $\frac{\pi}{6}$

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Consider the function $f : \mathbb{R} \rightarrow \mathbb{R}$ defined by $f(x) = \begin{cases} (2 - \sin(\frac{1}{x}))|x|, & x \neq 0 \\ 0, & x = 0 \end{cases}$. Then $f$ is

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Let $f$ be a real-valued function defined on the interval $(0, \infty)$ by $f(x)=\ln x+\int_0^x \sqrt{1+\sin t} \, dt$. Then which of the following statement$(s)$ is (are) true?
$(A)$ $f^{\prime \prime}(x)$ exists for all $x \in(0, \infty)$
$(B)$ $f^{\prime}(x)$ exists for all $x \in(0, \infty)$ and $f^{\prime}$ is continuous on $(0, \infty)$,but not differentiable on $(0, \infty)$
$(C)$ there exists $\alpha>1$ such that $|f^{\prime}(x)|<|f(x)|$ for all $x \in(\alpha, \infty)$
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In the following $[x]$ denotes the greatest integer less than or equal to $x$. Match the functions in Column $I$ with the properties in Column $II$.
Column $I$ Column $II$
$(A)$ $f(x) = x|x|$ $(p)$ continuous in $(-1, 1)$
$(B)$ $f(x) = \sqrt{|x|}$ $(q)$ differentiable in $(-1, 1)$
$(C)$ $f(x) = x + [x]$ $(r)$ strictly increasing in $(-1, 1)$
$(D)$ $f(x) = |x - 1| + |x + 1|$ $(s)$ not differentiable at least at one point in $(-1, 1)$

The functions $u = e^x \sin x$ and $v = e^x \cos x$ satisfy which of the following equations?

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