यदि $y = \frac{(\sin^{-1} x)^2}{2}$ है, तो $(1-x^2) y_2 - x y_1 = $

  • A
    $y$
  • B
    $2y$
  • C
    $1$
  • D
    $2$

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यदि $y = \sin^{-1} x$ है,तो $(1 - x^2) y_2 - x y_1 = $

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