If $u = x y^2 \tan^{-1}\left(\frac{y}{x}\right)$, then $x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y}$ is equal to

  • A
    $2 u$
  • B
    $u$
  • C
    $3 u$
  • D
    $\frac{1}{3} u$

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