If O is the origin and A is the point (a, b, | vedclass

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(C) The normal vector to the plane is the vector $\vec{OA}$.Since $O = (0, 0, 0)$ and $A = (a, b, c)$,the direction ratios of the normal vector $\vec{

Vedclass · Accepted Answer

$a(x - a) + b(y - b) + c(z - c) = 0$

Vedclass · Answer

(C) The normal vector to the plane is the vector $\vec{OA}$.Since $O = (0, 0, 0)$ and $A = (a, b, c)$,the direction ratios of the normal vector $\vec{OA}$ are $(a - 0, b - 0, c - 0)$,which are $a, b, c$.The equation of a plane passing through a point $(x_1, y_1, z_1)$ with normal vector $(A, B, C)$ is given by $A(x - x_1) + B(y - y_1) + C(z - z_1) = 0$.Substituting the point $A(a, b, c)$ and the normal vector $(a, b, c)$ into the formula:$a(x - a) + b(y - b) + c(z - c) = 0$.Thus,the correct option is $C$.

If $O$ is the origin and $A$ is the point $(a, b, c)$,then the equation of the plane passing through $A$ and perpendicular to $OA$ is:

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