If $\omega \neq 1$ is a cube root of unity, then the sum of the series $S = 1 + 2\omega + 3\omega^2 + \dots + 3n\omega^{3n-1}$ is

  • A
    $\frac{3n}{\omega-1}$
  • B
    $3n(\omega-1)$
  • C
    $\frac{\omega-1}{3n}$
  • D
    $0$

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