If 33theta = pi, then the value of cos theta | vedclass

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(B) Let $P = \cos 	heta \cos 2	heta \cos 4	heta \cos 8	heta \cos 16	heta$.Multiply and divide by $2^5 \sin 	heta$:$P = \frac{2^5 \sin 	heta \co

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$\frac{1}{32}$

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(B) Let $P = \cos 	heta \cos 2	heta \cos 4	heta \cos 8	heta \cos 16	heta$.Multiply and divide by $2^5 \sin 	heta$:$P = \frac{2^5 \sin 	heta \cos 	heta \cos 2	heta \cos 4	heta \cos 8	heta \cos 16	heta}{32 \sin 	heta}$.Using the formula $\sin 2A = 2 \sin A \cos A$ repeatedly:$P = \frac{\sin 32	heta}{32 \sin 	heta}$.Given $33	heta = \pi$, we have $32	heta = \pi - 	heta$.Thus, $\sin 32	heta = \sin(\pi - 	heta) = \sin 	heta$.Substituting this into the expression for $P$:$P = \frac{\sin 	heta}{32 \sin 	heta} = \frac{1}{32}$.

If $33\theta = \pi$, then the value of $\cos \theta \cos 2\theta \cos 4\theta \cos 8\theta \cos 16\theta$ is

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