If p to (q lor sim r) is false, then the trut | vedclass

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(C) $1$. The implication $p 	o (q \lor \sim r)$ is false only when $p$ is $T$ and $(q \lor \sim r)$ is $F$.$2$. For $(q \lor \sim r)$ to be $F$, both

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$F, T$

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(C) $1$. The implication $p 	o (q \lor \sim r)$ is false only when $p$ is $T$ and $(q \lor \sim r)$ is $F$.$2$. For $(q \lor \sim r)$ to be $F$, both $q$ must be $F$ and $\sim r$ must be $F$. Thus, $q = F$ and $r = T$.$3$. Now, evaluate $(p \leftrightarrow q) \land r$: Since $p = T, q = F$, then $(T \leftrightarrow F)$ is $F$. Thus, $F \land T = F$.$4$. Evaluate $\sim p 	o \sim q$: Since $p = T$ and $q = F$, then $\sim p = F$ and $\sim q = T$. The implication $F 	o T$ is $T$.$5$. The truth values are $F$ and $T$ respectively.

If $p \to (q \lor \sim r)$ is false, then the truth values of $(p \leftrightarrow q) \land r$ and $\sim p \to \sim q$ are :

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