If $f(x) = \begin{cases} \frac{(8-2x)^{\frac{1}{3}} - 2}{3 - (243+5x)^{\frac{1}{5}}}, & x \neq 0 \\ k, & x = 0 \end{cases}$ is continuous at $x = 0$, then $k =$

  • A
    $\frac{5}{2}$
  • B
    $-\frac{5}{2}$
  • C
    $\frac{27}{2}$
  • D
    $-\frac{27}{2}$

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