If x = a(cos theta + theta sin theta ) and y | vedclass

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(B) Given parametric equations are $x = a(\cos 	heta + 	heta \sin 	heta )$ and $y = a(\sin 	heta - 	heta \cos 	heta )$.First,differentiate $x$ w

Vedclass · Accepted Answer

$	an 	heta $

Vedclass · Answer

(B) Given parametric equations are $x = a(\cos 	heta + 	heta \sin 	heta )$ and $y = a(\sin 	heta - 	heta \cos 	heta )$.First,differentiate $x$ with respect to $	heta$:$\frac{dx}{d	heta} = a[-\sin 	heta + (\sin 	heta + 	heta \cos 	heta)] = a	heta \cos 	heta$.Next,differentiate $y$ with respect to $	heta$:$\frac{dy}{d	heta} = a[\cos 	heta - (\cos 	heta - 	heta \sin 	heta)] = a	heta \sin 	heta$.Now,find $\frac{dy}{dx}$ using the chain rule:$\frac{dy}{dx} = \frac{dy/d	heta}{dx/d	heta} = \frac{a	heta \sin 	heta}{a	heta \cos 	heta} = 	an 	heta$.

If $x = a(\cos \theta + \theta \sin \theta )$ and $y = a(\sin \theta - \theta \cos \theta )$,then $\frac{dy}{dx} = $

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