If $A$ and $B$ are two events such that $P(A \cup B) + P(A \cap B) = \frac{7}{8}$ and $P(A) = 2P(B)$, then $P(A) = $

  • A
    $\frac{7}{12}$
  • B
    $\frac{7}{24}$
  • C
    $\frac{5}{12}$
  • D
    $\frac{17}{24}$

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