If m is the mass of the _Z{X^A} nucleus,and m | vedclass

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(A) The mass of a nucleus is always less than the sum of the masses of its individual constituent nucleons (protons and neutrons). This difference in

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$m < (A - Z)m_n + Zm_p$

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(A) The mass of a nucleus is always less than the sum of the masses of its individual constituent nucleons (protons and neutrons). This difference in mass is known as the mass defect $(\Delta m)$,which is converted into binding energy according to Einstein's mass-energy equivalence principle $(E = \Delta mc^2)$.Given that the nucleus $_Z{X^A}$ contains $Z$ protons and $(A - Z)$ neutrons,the sum of the masses of the individual nucleons is $(A - Z)m_n + Zm_p$.Since the mass of the nucleus $m$ is less than the sum of the masses of its constituents due to the mass defect,we have:$m < (A - Z)m_n + Zm_p$.

If $m$ is the mass of the $_Z{X^A}$ nucleus,and $m_n$ and $m_p$ are the masses of a neutron and a proton respectively,then which of the following is correct?

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