If $\frac{(x - 1)^2}{x^3 + x} = \frac{A}{x} + \frac{Bx + C}{x^2 + 1}$,then

  • A
    $A = 1, B = 0, C = -2$
  • B
    $A = 1, B = 0, C = 2$
  • C
    $A = -1, B = 0, C = -2$
  • D
    None of these

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