If A = begin{bmatrix} 1 & a 0 & 1 end{bmatri | vedclass

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(A) We have $A^2 = \begin{bmatrix} 1 & a \ 0 & 1 \end{bmatrix} \begin{bmatrix} 1 & a \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 2a \ 0 & 1 \end{bm

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$\begin{bmatrix} 1 & na \ 0 & 1 \end{bmatrix}$

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(A) We have $A^2 = \begin{bmatrix} 1 & a \ 0 & 1 \end{bmatrix} \begin{bmatrix} 1 & a \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 2a \ 0 & 1 \end{bmatrix}$.$A^3 = A^2 A = \begin{bmatrix} 1 & 2a \ 0 & 1 \end{bmatrix} \begin{bmatrix} 1 & a \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 3a \ 0 & 1 \end{bmatrix}$.By observing the pattern,we can generalize this using mathematical induction. For any $n \in N$,$A^n = \begin{bmatrix} 1 & na \ 0 & 1 \end{bmatrix}$.

If $A = \begin{bmatrix} 1 & a \\ 0 & 1 \end{bmatrix}$,then $A^n$ (where $n \in N$) equals

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