If $X(OH) > Y(OH)$ (acidic strength) and $X$ and $Y$ both belong to the same group,then select the $CORRECT$ statement:

  • A
    Electron gain enthalpy of $Y$ must be greater than $X$
  • B
    Atomic size of $X$ must be greater than $Y$
  • C
    $O-H$ bond will be easily broken in case of hydroxide of $X$
  • D
    $O-H$ bond will be easily broken in case of hydroxide of $Y$

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The element with $Z = 120$ (not yet discovered) will be a/an:

The electronic configuration of an element is $1s^2, 2s^2 2p^6, 3s^2 3p^3$. What is the atomic number of the element which is just below the above element in the periodic table?

Which of the following is the correct order of increasing density for the given elements?

The first $(\Delta_{i} H_{1})$ and the second $(\Delta_{i} H_{2})$ ionization enthalpies (in $kJ \ mol^{-1}$) and the $(\Delta_{eg} H)$ electron gain enthalpy (in $kJ \ mol^{-1}$) of a few elements are given below:
Elements $\Delta_{i} H_{1}$ $\Delta_{i} H_{2}$ $\Delta_{eg} H$
$I$ $520$ $7300$ $-60$
$II$ $419$ $3051$ $-48$
$III$ $1681$ $3374$ $-328$
$IV$ $1008$ $1846$ $-295$
$V$ $2372$ $5251$ $+48$
$VI$ $738$ $1451$ $-40$

Which of the above elements is likely to be:
$(a)$ the least reactive element.
$(b)$ the most reactive metal.
$(c)$ the most reactive non-metal.
$(d)$ the least reactive non-metal.
$(e)$ the metal which can form a stable binary halide of the formula $MX_{2}$ $(X = \text{halogen})$.
$(f)$ the metal which can form a predominantly stable covalent halide of the formula $MX$ $(X = \text{halogen})$?

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Which will show maximum non-metallic character?

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