If a coil is open,then its self-inductance L | vedclass

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(B) When a coil is open,the circuit is broken,meaning no current can flow through it $(i = 0)$.Since the circuit is open,the resistance $R$ of the pat

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$0, \infty$

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(B) When a coil is open,the circuit is broken,meaning no current can flow through it $(i = 0)$.Since the circuit is open,the resistance $R$ of the path is effectively infinite $(R = \infty)$.Regarding self-inductance $L$,it is defined as the property of the coil to oppose any change in current. Mathematically,$\phi = Li$,where $\phi$ is the magnetic flux.For an open coil,there is no current $(i = 0)$,and consequently,no magnetic flux is generated by the coil $(\phi = 0)$.Thus,$L = \frac{\phi}{i} = \frac{0}{0}$. In the context of an open circuit,the ability to store magnetic energy or induce an $EMF$ is absent,leading to $L = 0$.

If a coil is open,then its self-inductance $L$ and resistance $R$ become:

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