If a function f: R rightarrow R is defined by | vedclass

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(B) To find the inverse function $f^{-1}(x)$,we set $f(x) = y$. $y = \frac{4x}{5} + 3$ Subtract $3$ from both sides: $y - 3 = \frac{4x}{5}$ Multiply b

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$\frac{5(x-3)}{4}$

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(B) To find the inverse function $f^{-1}(x)$,we set $f(x) = y$. $y = \frac{4x}{5} + 3$ Subtract $3$ from both sides: $y - 3 = \frac{4x}{5}$ Multiply both sides by $5$: $5(y - 3) = 4x$ Divide by $4$: $x = \frac{5(y - 3)}{4}$ Since $x = f^{-1}(y)$,we have $f^{-1}(y) = \frac{5(y - 3)}{4}$. Replacing $y$ with $x$,we get: $f^{-1}(x) = \frac{5(x - 3)}{4}$ Thus,the correct option is $B$.

If a function $f: R \rightarrow R$ is defined by $f(x) = \frac{4x}{5} + 3$,then $f^{-1}(x) =$

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