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(B) The set of given digits is ${2, 3, 5, 7, 9}$. The total number of digits is $n = 5$.To form a two-digit number without repetition,we need to selec

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$\frac{1}{20}$

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(B) The set of given digits is ${2, 3, 5, 7, 9}$. The total number of digits is $n = 5$.To form a two-digit number without repetition,we need to select and arrange $2$ digits out of $5$.The total number of possible outcomes (sample space $S$) is given by the permutation formula $^nP_r = \frac{n!}{(n-r)!}$.Here,$n(S) = ^5P_2 = \frac{5!}{(5-2)!} = 5 	imes 4 = 20$.The event $E$ is that the number formed is $35$. Since $35$ is a specific outcome,$n(E) = 1$.The probability $P(E)$ is given by $\frac{n(E)}{n(S)} = \frac{1}{20}$.

If a number of two digits is formed with the digits $2, 3, 5, 7, 9$ without repetition of digits,what is the probability that the number formed is $35$?

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