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(B) Let the radius of the circle be $r$.Then,the diameter of the circle $= 2r$.Since the square is inscribed in the circle,the diagonal of the square

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$\pi: 2$

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(B) Let the radius of the circle be $r$.Then,the diameter of the circle $= 2r$.Since the square is inscribed in the circle,the diagonal of the square is equal to the diameter of the circle.Diagonal of square $= 2r$.Let the side of the square be $a$.Then,$a\sqrt{2} = 2r$,which implies $a = \frac{2r}{\sqrt{2}} = r\sqrt{2}$.Area of the circle $= \pi r^2$.Area of the square $= a^2 = (r\sqrt{2})^2 = 2r^2$.Required ratio $= \frac{	ext{Area of circle}}{	ext{Area of square}} = \frac{\pi r^2}{2r^2} = \frac{\pi}{2}$.Thus,the ratio is $\pi: 2$.

If a square is inscribed in a circle,the ratio of the area of the circle and the square is

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