If a step-up transformer has a turn ratio of $5$,a frequency of $50 \, Hz$,the root mean square $(RMS)$ value of the potential difference on the primary is $100 \, V$,and the resistance of the secondary winding is $500 \, \Omega$,then the peak value of the voltage in the secondary winding will be (the efficiency of the transformer is $100 \%$).

  • A
    $500 \sqrt{2} \, V$
  • B
    $10 \sqrt{2} \, V$
  • C
    $50 \sqrt{2} \, V$
  • D
    $20 \sqrt{2} \, V$

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