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(A) For an electromagnetic wave propagating in a vacuum,the relationship between the amplitudes of the electric field $(E_0)$ and the magnetic field $

Vedclass · Accepted Answer

$E_0 k = B_0 \omega$

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(A) For an electromagnetic wave propagating in a vacuum,the relationship between the amplitudes of the electric field $(E_0)$ and the magnetic field $(B_0)$ is given by the equation $c = \frac{E_0}{B_0}$,where $c$ is the speed of light in a vacuum.The speed of the wave is also related to the angular frequency $(\omega)$ and the wave number $(k)$ by the expression $c = \frac{\omega}{k}$.Equating these two expressions for $c$,we get $\frac{E_0}{B_0} = \frac{\omega}{k}$.By cross-multiplying,we obtain $E_0 k = B_0 \omega$.Therefore,the correct option is $A$.

If an electromagnetic wave propagating through vacuum is described by $E_y = E_0 \sin(kx - \omega t)$ and $B_z = B_0 \sin(kx - \omega t)$,then:

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