For a plane electromagnetic wave,E_x = 0,E_y | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given equation for the electric field is $E_y = E_0 \cos(\omega t - kx)$.Comparing this with the standard form of a wave traveling in the posi

Vedclass · Accepted Answer

The wave propagates in the positive $X$ direction with a wavelength of $200 \ m$ and a frequency of $10^6 \ Hz$.

Vedclass · Answer

(B) The given equation for the electric field is $E_y = E_0 \cos(\omega t - kx)$.Comparing this with the standard form of a wave traveling in the positive $X$ direction,we identify the angular frequency $\omega = 2\pi 	imes 10^6 \ rad/s$ and the wave number $k = \pi 	imes 10^{-2} \ rad/m$.The frequency $f$ is given by $\omega = 2\pi f$,so $2\pi f = 2\pi 	imes 10^6 \implies f = 10^6 \ Hz$.The wavelength $\lambda$ is given by $k = \frac{2\pi}{\lambda}$,so $\frac{2\pi}{\lambda} = \pi 	imes 10^{-2} \implies \lambda = \frac{2}{\pi 	imes 10^{-2}} 	imes \pi = 200 \ m$.Since the phase is $(\omega t - kx)$,the wave propagates in the positive $X$ direction.

For a plane electromagnetic wave,$E_x = 0$,$E_y = 2.5 \frac{N}{C} \cos \left[ (2\pi \times 10^6 \frac{rad}{s})t - (\pi \times 10^{-2} \frac{rad}{m})x \right]$,and $E_z = 0$. Which of the following is true?

Similar Questions

The velocity of an electromagnetic wave in a medium is $2.5 \times 10^{8} \ m/s$. What is the dielectric constant of the medium?

In vacuum,the speed of light depends upon

In a plane electromagnetic wave,the electric field oscillates sinusoidally at a frequency of $2 \times 10^{10} \, Hz$ and an amplitude of $48 \, V/m$. Find the amplitude of the magnetic field.

The mean intensity of radiation on the surface of the Sun is about $10^{8} \ W/m^2$. The $rms$ value of the corresponding magnetic field is closest to

Vedclass Test Series

Exam Paper Generator

Online Exam Module