If an emitter current is changed by 4, mA,the | vedclass

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(A) The relationship between emitter current $(I_E)$,collector current $(I_C)$,and base current $(I_B)$ is given by $I_E = I_C + I_B$.For small change

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(A) The relationship between emitter current $(I_E)$,collector current $(I_C)$,and base current $(I_B)$ is given by $I_E = I_C + I_B$.For small changes,this can be written as $\Delta I_E = \Delta I_C + \Delta I_B$.Given $\Delta I_E = 4\, mA$ and $\Delta I_C = 3.5\, mA$,we find the change in base current:$\Delta I_B = \Delta I_E - \Delta I_C = 4\, mA - 3.5\, mA = 0.5\, mA$.The current gain $\beta$ is defined as the ratio of change in collector current to the change in base current:$\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{3.5\, mA}{0.5\, mA} = 7$.Therefore,the value of $\beta$ is $7$.

If an emitter current is changed by $4\, mA$,the collector current changes by $3.5\, mA$. The value of $\beta$ will be

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