If four gases A,B,C and D have Henry's consta | vedclass

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(B) According to Henry's Law,the solubility of a gas is given by $S = \frac{P}{K_H}$,where $P$ is the partial pressure and $K_H$ is Henry's constant.S

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$B$

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(B) According to Henry's Law,the solubility of a gas is given by $S = \frac{P}{K_H}$,where $P$ is the partial pressure and $K_H$ is Henry's constant.Since the partial pressure $P$ is constant for all gases,the solubility $S$ is inversely proportional to $K_H$ $(S \propto \frac{1}{K_H})$.Therefore,the gas with the minimum $K_H$ value will have the maximum solubility.Comparing the given $K_H$ values:$A: 1.9 	imes 10^1 \ bar$$B: 6.5 	imes 10^{-4} \ bar$$C: 7.8 	imes 10^{-4} \ bar$$D: 6.0 	imes 10^3 \ bar$The minimum value is $6.5 	imes 10^{-4} \ bar$,which corresponds to gas $B$.

If four gases $A$,$B$,$C$ and $D$ have Henry's constant $(K_H)$ values $1.9 \times 10^1 \ bar$,$6.5 \times 10^{-4} \ bar$,$7.8 \times 10^{-4} \ bar$ and $6.0 \times 10^3 \ bar$ respectively,then which of the following gas has maximum solubility at the same partial pressure?

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