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(C) The equation of the circle is $(x - 2)^2 + y^2 = 1$,which expands to $x^2 - 4x + 4 + y^2 = 1$,or $x^2 + y^2 - 4x + 3 = 0$.The equation of the chor

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$\sqrt{3}$

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(C) The equation of the circle is $(x - 2)^2 + y^2 = 1$,which expands to $x^2 - 4x + 4 + y^2 = 1$,or $x^2 + y^2 - 4x + 3 = 0$.The equation of the chord of contact from the origin $(0, 0)$ is given by $T = 0$,where $T$ is the tangent equation form.Substituting $(x_1, y_1) = (0, 0)$ into the circle equation $x^2 + y^2 + 2gx + 2fy + c = 0$ gives $xx_1 + yy_1 + g(x + x_1) + f(y + y_1) + c = 0$.Here $g = -2, f = 0, c = 3$,so the equation is $0 + 0 - 2(x + 0) + 0(y + 0) + 3 = 0$,which simplifies to $-2x + 3 = 0$ or $x = \frac{3}{2}$.The distance $d$ from the center $(2, 0)$ to the chord $x = \frac{3}{2}$ is $d = |2 - \frac{3}{2}| = \frac{1}{2}$.The radius $r$ of the circle is $1$.The length of the chord of contact is $2\sqrt{r^2 - d^2} = 2\sqrt{1^2 - (\frac{1}{2})^2} = 2\sqrt{1 - \frac{1}{4}} = 2\sqrt{\frac{3}{4}} = 2 	imes \frac{\sqrt{3}}{2} = \sqrt{3}$.

If from the origin two tangents are drawn to the circle $(x - 2)^2 + y^2 = 1$,then the length of the chord of contact is-

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