If in a long division sum,the dividend is $380606$ and the successive remainders from the first to the last are $434, 125,$ and $413,$ then the divisor is:

  • A
    $451$
  • B
    $843$
  • C
    $4215$
  • D
    $3372$

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Which fraction among $\frac{2}{3}$,$\frac{4}{5}$,and $\frac{7}{11}$ is the largest?

$0.01024 \times (0.4)^{9} = (0.4)^{?} \times (0.0256)^{3}$

$\frac{(0.6^{3}-0.1^{3}-0.4^{3}-3 \times 0.6 \times 0.1 \times 0.4)}{(0.6^{2}+0.1^{2}+0.4^{2}+0.6 \times 0.1+0.6 \times 0.4-0.1 \times 0.4)}$

$\sqrt{6+\sqrt{6+\sqrt{6+\cdots}}} = ?$

$1599 \times 199 \div 49 - 1398 + 3877 = ?$

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