If in triangles ABC and DEF,frac{AB}{DE} = fr | vedclass

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(D) For two triangles to be similar by the $SAS$ (Side-Angle-Side) similarity criterion,the ratio of two corresponding sides must be equal,and the inc

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$\angle B = \angle D$

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(D) For two triangles to be similar by the $SAS$ (Side-Angle-Side) similarity criterion,the ratio of two corresponding sides must be equal,and the included angle between these sides must be equal.Given the ratio $\frac{AB}{DE} = \frac{BC}{FD}$,the sides $AB$ and $BC$ form the angle $\angle B$ in $	riangle ABC$. Similarly,the sides $DE$ and $FD$ form the angle $\angle D$ in $	riangle DEF$.Therefore,for $	riangle ABC \sim 	riangle EDF$,the included angles must be equal,i.e.,$\angle B = \angle D$.

If in triangles $ABC$ and $DEF$,$\frac{AB}{DE} = \frac{BC}{FD}$,then they will be similar,when

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