If in two triangles DEF and PQR,angle D = ang | vedclass

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(D) Given,in $	riangle DEF$ and $	riangle PQR$,$\angle D = \angle Q$ and $\angle E = \angle R$.By the $AA$ similarity criterion,$	riangle DEF \sim

Vedclass · Accepted Answer

$\frac{DE}{PQ} = \frac{EF}{RP}$

Vedclass · Answer

(D) Given,in $	riangle DEF$ and $	riangle PQR$,$\angle D = \angle Q$ and $\angle E = \angle R$.By the $AA$ similarity criterion,$	riangle DEF \sim 	riangle QRP$.Since the triangles are similar,the ratios of their corresponding sides are equal:$\frac{DE}{QR} = \frac{EF}{RP} = \frac{DF}{QP}$.Now,let's check the given options:Option $A$: $\frac{EF}{PR} = \frac{DF}{PQ}$ is equivalent to $\frac{EF}{RP} = \frac{DF}{QP}$,which is true.Option $B$: $\frac{EF}{RP} = \frac{DE}{QR}$ is true.Option $C$: $\frac{DE}{QR} = \frac{DF}{PQ}$ is equivalent to $\frac{DE}{QR} = \frac{DF}{QP}$,which is true.Option $D$: $\frac{DE}{PQ} = \frac{EF}{RP}$. From the similarity ratio,$\frac{DE}{QR} = \frac{EF}{RP}$. Thus,$\frac{DE}{PQ} = \frac{EF}{RP}$ is not necessarily true because $PQ 
eq QR$ in general.Therefore,option $D$ is not true.

If in two triangles $DEF$ and $PQR$,$\angle D = \angle Q$ and $\angle R = \angle E$,then which of the following is not true?

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