If the line $\frac{2x - 8}{\sin \beta} = \frac{y - \sin \alpha}{1} = \frac{z - 1}{\cos \alpha}$,where $\beta \in R$ and $\sin \beta \neq 1$,lies in the plane $2x - (\sin \beta)y + (\cos \beta)z = k$ for all $\alpha \in R$,then:

  • A
    $k = 8 - \sin \alpha$
  • B
    $k = 8 + \sin \alpha$
  • C
    $k = 8 - \cos \beta$
  • D
    None of these

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