If one of the lines of the pair ax^2 + 2hxy + | vedclass

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(B) The bisector of the angle between the positive directions of the axes is the line $y = x$.Since this line is one of the lines represented by the p

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$a + b = -2h$

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(B) The bisector of the angle between the positive directions of the axes is the line $y = x$.Since this line is one of the lines represented by the pair $ax^2 + 2hxy + by^2 = 0$,it must satisfy the equation.Substituting $y = x$ into the equation,we get:$ax^2 + 2hx(x) + b(x)^2 = 0$$ax^2 + 2hx^2 + bx^2 = 0$$x^2(a + 2h + b) = 0$Since this holds for all $x$,we must have $a + 2h + b = 0$,which simplifies to $a + b = -2h$.

If one of the lines of the pair $ax^2 + 2hxy + by^2 = 0$ bisects the angle between the positive directions of the axes,then $a, b, h$ satisfy the relation:

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