If only 2% of the main current is to be passe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the main current be $I$ and the current through the galvanometer be $I_g$.Given that $I_g = 2\%$ of $I$,so $I_g = \frac{2}{100} I = \frac{I}{5

Vedclass · Accepted Answer

$\frac{G}{49}$

Vedclass · Answer

(B) Let the main current be $I$ and the current through the galvanometer be $I_g$.Given that $I_g = 2\%$ of $I$,so $I_g = \frac{2}{100} I = \frac{I}{50}$.Let $S$ be the shunt resistance connected in parallel to the galvanometer of resistance $G$.The formula for the current through the galvanometer is $I_g = I \left( \frac{S}{S + G} \right)$.Substituting the values: $\frac{I}{50} = I \left( \frac{S}{S + G} \right)$.$\frac{1}{50} = \frac{S}{S + G} \Rightarrow S + G = 50S$.$G = 49S \Rightarrow S = \frac{G}{49}$.

If only $2\%$ of the main current is to be passed through a galvanometer of resistance $G$,then the resistance of the shunt will be

Similar Questions

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is:

An ammeter reads up to $1\, A$. Its internal resistance is $0.81\, \Omega$. To increase the range to $10\, A$,the value of the required shunt is ............ $\Omega$.

If the current is doubled,the deflection is also doubled in

$A$ voltmeter of range $3 \, V$ and resistance $200 \, \Omega$ cannot be converted to an ammeter of range

Why should the resistance of an ammeter be as low as possible?

Vedclass Test Series

Exam Paper Generator

Online Exam Module